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    IBMediumNumber10–12

    Expand (2+3i)(1−i)(2 + 3i)(1 - i) and write the result in the form a+bia + bi.

    Desenvolve (2+3i)(1−i)(2 + 3i)(1 - i) e escreve o resultado na forma a+bia + bi.

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    Solution

    Step 1 of 3

    1. 1.(2+3i)(1−i)=2−2i+3i−3i2(2 + 3i)(1 - i) = 2 - 2i + 3i - 3i^{2}