← Back to the programme
    IBHardFunctions10–12

    Solve 22x−5×2x+4=02^{2x} - 5 \times 2^{x} + 4 = 0. What is the largest value of xx?

    Resolve 22x−5×2x+4=02^{2x} - 5 \times 2^{x} + 4 = 0. Qual é o maior valor de xx?

    Answer options

    Solution

    Step 1 of 4

    1. 1.Let y=2xy = 2^{x}, so y2−5y+4=0y^{2} - 5y + 4 = 0