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    IBHardCalculus10–12

    What is ddx[ln⁡(sin⁡x)]\frac{d}{dx}[\ln(\sin x)]?

    Qual é ddx[ln⁡(sin⁡x)]\frac{d}{dx}[\ln(\sin x)]?

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    Solution

    By chain rule: ddx[ln⁡(sin⁡x)]=1sin⁡x×cos⁡x=cos⁡xsin⁡x=cot⁡x\frac{d}{dx}[\ln(\sin x)] = \frac{1}{\sin x} \times \cos x = \frac{\cos x}{\sin x} = \cot x