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IB
Hard
Vectors
10–12
Find the angle between vectors
(
1
,
1
,
0
)
(1, 1, 0)
(
1
,
1
,
0
)
and
(
0
,
1
,
1
)
(0, 1, 1)
(
0
,
1
,
1
)
.
Determina o ângulo entre os vetores
(
1
,
1
,
0
)
(1, 1, 0)
(
1
,
1
,
0
)
e
(
0
,
1
,
1
)
(0, 1, 1)
(
0
,
1
,
1
)
.
Answer options
A.
60
∘
60^\circ
6
0
∘
B.
45
∘
45^\circ
4
5
∘
C.
90
∘
90^\circ
9
0
∘
D.
30
∘
30^\circ
3
0
∘
Check Answer
Solution
Step 1 of 2
1.
a
⃗
⋅
b
⃗
=
0
+
1
+
0
=
1
\vec{a} \cdot \vec{b} = 0+1+0 = 1
a
⋅
b
=
0
+
1
+
0
=
1
.
∣
a
⃗
∣
=
2
|\vec{a}| = \sqrt{2}
∣
a
∣
=
2
,
∣
b
⃗
∣
=
2
|\vec{b}| = \sqrt{2}
∣
b
∣
=
2
.
Next step
Show full solution