← Back to the programme
    IBHardVectors10–12

    Vector Cross Product

    Produto Vetorial

    Find the cross product of a⃗=(1,2,3)\vec{a} = (1, 2, 3) and b⃗=(4,5,6)\vec{b} = (4, 5, 6). What is the area of the parallelogram formed by these vectors?

    a⃗×b⃗=(a2b3−a3b2,a3b1−a1b3,a1b2−a2b1)\vec{a} \times \vec{b} = (a_2b_3 - a_3b_2, a_3b_1 - a_1b_3, a_1b_2 - a_2b_1). Area =∣a⃗×b⃗∣= |\vec{a} \times \vec{b}|.

    Solution

    Step 1 of 4

    1. 1.a⃗×b⃗=(2⋅6−3⋅5,3⋅4−1⋅6,1⋅5−2⋅4)\vec{a} \times \vec{b} = (2 \cdot 6 - 3 \cdot 5, 3 \cdot 4 - 1 \cdot 6, 1 \cdot 5 - 2 \cdot 4)