ONE
    Númas
    ← Back to the programme
    IBMediumFunctions10–12

    Quadratic Functions

    Funções Quadráticas

    Find the vertex and axis of symmetry of f(x)=−2(x−3)2+8f(x) = -2(x - 3)^{2} + 8. State the maximum value.

    The vertex form is f(x)=a(x−h)2+kf(x) = a(x - h)^{2} + k where (h,k)(h, k) is the vertex.

    Solution

    Step 1 of 4

    1. 1.Vertex =(3,8)= (3, 8)