← Back to the programme
    NationalHardAlgebra7–9

    Quadratic Equations

    Equações do 2º Grau

    A rectangular field has a perimeter of 6060 m and an area of 200 m2200 \text{ m}^{2}. Find the dimensions of the field.

    Let length =l= l and width =w= w. You know 2(l+w)=602(l + w) = 60 and l×w=200l \times w = 200. Express ll in terms of ww, then solve the quadratic.

    Solution

    Step 1 of 8

    1. 1.2(l+w)=60⇒l+w=30⇒l=30−w2(l + w) = 60 \Rightarrow l + w = 30 \Rightarrow l = 30 - w