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    NationalHardGeometry7–9

    Trigonometry Basics

    Trigonometria Básica

    From a point 5050 m from the base of a tower, the angle of elevation to the top is 35∘35^\circ. Find the height of the tower. Use tan⁡(35∘)≈0.7002\tan(35^\circ) \approx 0.7002.

    A right-angled triangle drawn to scale. The tower stands vertically at the right; the ground runs 50 metres from the observer to its base. The line of sight to the top makes an angle of 35 degrees with the ground, and the height of the tower is marked with a question mark.35°50 m?

    tan⁡(angle)=oppositeadjacent=heightdistance\tan(\text{angle}) = \dfrac{\text{opposite}}{\text{adjacent}} = \dfrac{\text{height}}{\text{distance}}

    Solution

    Step 1 of 5

    1. 1.tan⁡(35∘)=h50\tan(35^\circ) = \dfrac{h}{50}