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    NationalMediumProbability10–12

    Given P(A∩B)=0.12P(A \cap B) = 0.12 and P(B)=0.3P(B) = 0.3, what is P(A∣B)P(A \mid B)?

    Sabendo que P(A∩B)=0,12P(A \cap B) = 0{,}12 e P(B)=0,3P(B) = 0{,}3, qual é P(A∣B)P(A \mid B)?

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    Solution

    Step 1 of 3

    1. 1.Conditional probability: P(A∣B)=P(A∩B)P(B)P(A \mid B) = \frac{P(A \cap B)}{P(B)}