ONE
All Portugal
Númas
EN
Sign in
← Back to the programme
Olympiad
Easy
Number Theory
10–12
What are the last two digits of
7
2026
7^{2026}
7
2026
?
Quais são os dois últimos algarismos de
7
2026
7^{2026}
7
2026
?
Answer options
A.
7
B.
43
C.
49
D.
1
Check Answer
Solution
Step 1 of 3
1.
Work modulo
100
100
100
:
7
1
=
7
7^{1} = 7
7
1
=
7
,
7
2
=
49
7^{2} = 49
7
2
=
49
,
7
3
=
343
≡
43
7^{3} = 343 \equiv 43
7
3
=
343
≡
43
,
7
4
=
2401
≡
1
7^{4} = 2401 \equiv 1
7
4
=
2401
≡
1
.
Next step
Show full solution