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    OlympiadMediumNumber Theory10–12

    What is the remainder when 3473^{47} is divided by 2323?

    Qual é o resto da divisão de 3473^{47} por 2323?

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    Solution

    Step 1 of 3

    1. 1.2323 is prime and 23∤323 \nmid 3, so Fermat's little theorem gives 322≡1(mod23)3^{22} \equiv 1 \pmod{23}.