← Back to the programme
    OlympiadHardInequalities10–12

    For x>0x > 0, what is the minimum value of x2+16xx^{2} + \frac{16}{x}?

    Para x>0x > 0, qual é o valor mínimo de x2+16xx^{2} + \frac{16}{x}?

    Answer options

    Solution

    Step 1 of 3

    1. 1.Split the second term in two: x2+8x+8xx^{2} + \frac{8}{x} + \frac{8}{x}.