What is the distance from the point $(3, 4)$ to the line $3x + 4y + 5 = 0$?

$d = \frac{|3 \times 3 + 4 \times 4 + 5|}{\sqrt{3^{2} + 4^{2}}} = \frac{30}{5} = 6$. Forgetting to divide by the length of the normal vector leaves $30$.