Se 2x=82^{x} = 82x=8 e 3y=813^{y} = 813y=81, quanto vale x+yx + yx+y?
8=238 = 2^{3}8=23 gives x=3x = 3x=3, and 81=3481 = 3^{4}81=34 gives y=4y = 4y=4, so x+y=7x + y = 7x+y=7.