S∞=a1−r⇒20=121−r⇒1−r=1220=35⇒r=25S_\infty = \frac{a}{1-r} \Rightarrow 20 = \frac{12}{1-r} \Rightarrow 1-r = \frac{12}{20} = \frac{3}{5} \Rightarrow r = \frac{2}{5}S∞=1−ra⇒20=1−r12⇒1−r=2012=53⇒r=52